12x^2+63x+5=0

Solution for 12x^2+63x+5=0 equation:

12x^2+63x+5=0

a = 12; b = 63; c = +5;
Δ = b2-4ac
Δ = 632-4·12·5
Δ = 3729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-\sqrt{3729}}{2*12}=\frac{-63-\sqrt{3729}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+\sqrt{3729}}{2*12}=\frac{-63+\sqrt{3729}}{24}
$